Calculate the solubility in mol dm-3 of 40g of CuSO4 dissolved in 100g of water at 120oC.
[Cu = 64, S = 32, O = 16]
-
A.
4.00 -
B.
2.50 -
C.
0.40 -
D.
0.25
Correct Answer: Option B
Explanation
Solubility = (frac{text{number of moles of solution}}{text{vol of solution}})
100g of water = 100 cm(^3) = 0.1 dm(^3).
CuSO(_4) = 160 g/mol
No of moles of CuSO(_4) in 40g = (frac{40}{160})
= 0.25 mol.
Solubility = (frac{0.25}{0.1})
= 2.5 moldm(^{-3}).