Calculate the percentage composition of oxygen in calcium trioxocarbonate(IV) [Ca=40, C=12, O=16]
-
A.
16 -
B.
48 -
C.
40 -
D.
12
Correct Answer: Option B
Explanation
Calcium trioxocarbonate (IV) = CaCO(_3)
Percentage of Oxygen = (frac{text{Molar mass of 3O}}{text{Molar mass of} CaCO_3}) × 100%
Percentage of Oxygen = (frac{(3 times 16)}{(40 + 12 + 48)}) x 100%
Percentage of Oxygen = (frac{48}{100}) x 100%
Percentage of Oxygen = 48%
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