Calculate the mass of chlorine gas which occupies a volume of 1.12 dm(^3) a volume of 1.12 dm(^3) at s.t.p [Cl = 35.5, 1 mole og gas occupies 22.4 dm(^3) at s. t. p ]
-
A.
1.80g -
B.
3.55g -
C.
7.10g -
D.
15.50g
Correct Answer: Option B
Explanation
1 mole Cl(_2) occupy 22.4dm(^3)
i.e 2 x 35.5 → 22.4 ; x → 1. 12
:. x = (frac{1.12}{22.4}) x 2 x 35.5 = 3.55