Calculate the force acting on an electron of charge 1.5 x 10-19C placed in an electric field of intensity 105Vm-1
-
A.
1.5×10-11N -
B.
1.5×10-12N -
C.
1.5×10-13N -
D.
1.5×10-14N
Correct Answer: Option D
Explanation
F = qE
F = 1.5 x 10-19 x 105
F = 1.5 x 10-14N
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