caesium has a work function of 3 x 10-19J. the maximum energy of liberated electrons…

caesium has a work function of 3 x 10-19J. the maximum energy of liberated electrons when it is illuminated by light of frequency 6.7 x 1014
HZ is?
[h = 6.6 x 1010-34Js]
  • A.
    1.42 x 10-19J
  • B.
    3.00 x 10-19J
  • C.
    4.42 x 1010-19J
  • D.
    7.42 x 10-19J
Correct Answer: Option A
Explanation

Max kinetic energy = Energy of incident electron – work function. EK = hf – w
= 6.6 x 10-34 x 6.7 x 1014 – 3 x 10-19
= 4.422 x 10-19 – 3 x 10-19
= 1.422 x 10-19J

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