(begin{array}{c|c} x & 1 & 4 & p \ hline y & 0.5 & 1 & 2.5end{array}). The table above satisfies the relation y = k(sqrt{x}), where k is a positive constant. Find the value of K.
-
A.
0.5 -
B.
1 -
C.
1.5 -
D.
2
Correct Answer: Option A
Explanation
y = k(sqrt{x}) when y = 1, x = 4
k = (frac{y}{sqrt{x}})
= (frac{1}{sqrt{4}})
= (frac{1}{2})
= 0.5