(begin{array}{c|c} Scores(x) & 0 & 1 & 2 & 3 & 4 & 5 & 6 \ hline Frequency(f) & 7 & 11 & 6 & 7 & 7 & 5 & 3end{array})
In the distribution above, the mode and median respectively are
-
A.
1,3 -
B.
1, 2 -
C.
3, 3 -
D.
0, 2
Correct Answer: Option B
Explanation
From the distribution, Mode = 1 and
Median = (frac{2 + 2}{2})
= 2
= 1, 2