Atom (^{234} _{88} Q) decay by alpha emission to give an atom R. The atomic number and mass number of atom R are respectively
-
A.
86 and 230 -
B.
87 and 234 -
C.
88 and 233 -
D.
90 and 238
Correct Answer: Option A
Explanation
(^{234} _{88} Q to R + ^4 _2 He)
(therefore R = ^{234 – 4} _{88 – 2} R)
= (^{230} _{86} R)