An X-ray tube operates at a potential of 2500 V. If the power of the tube is 750 W, calculate the speed of the electron striking the target. [e = 1.6 x 10(^{-19}) C; mass of electron = 9.1 x 10(^{-3}) kg]
Explanation
(a) eV (frac{1}{2}MV^2)
V(^2 = frac{2eV}{m})
= (frac{2 times 1.6 times 10^{-19} times 2500}{9.1 times 10^{-31}})
V = (sqrt{8.79 times 10^{14}})
= 2.96 x 10(^{7})