An organic pipe closed at one end is 80cm long. Determine the frequency of the fundamental note assuming that the speed of sound in air is 340ms-1
-
A.
106Hz -
B.
213Hz -
C.
318Hz -
D.
425Hz
Correct Answer: Option A
Explanation
(lambda) = 4L
= 4 x 80 = 320cm
Converting 320cm to m, we have 3.2m
F = (frac{V}{lambda})
= (frac{340}{3.2})
= 106.25Hz
(approxeq) 106Hz