An object weighs 60.0N in air, 48.2N in a certain liquid X, and 44.9N in water, Calculate the relative density of X
-
A.
3.300 -
B.
1.279 -
C.
0.932 -
D.
0.782
Correct Answer: Option D
Explanation
R.d = Wt in Air-Wt in Air-Wt in water
= (frac{60.0 – 48.2}{60.0 – 44.9})
= 0.782