An object is protected with a velocity of 100m-1 at an angle of 60o to the vertical. Calculate the time taken by the object to reach the highest point (Take g as 10ms-2
-
A.
5.0s -
B.
8.7s -
C.
10.0s -
D.
17.3s -
E.
20.0s
Correct Answer: Option B
Explanation
t = (frac{T}{2} = frac{1}{2} = frac{2u sin theta}{g} = frac{100 times sin 60}{10})
10 sin60 = 10 x 0.8660
= 8.7