An object is projected with a velocity of 80ms-1 at an angle of 30o to the horizontal.The maximum height reached is
-
A.
20m -
B.
80m -
C.
160m -
D.
320m
Correct Answer: Option B
Explanation
max. height = (frac{U^2sin^2theta}{2g})
= (frac{80 times 80 times sin^2(30)}{2 times 10})
= 80m