An object is placed 10cm from a converging lens of foal length 15cm. Calculate the magnification of the image formed
-
A.
3.0 -
B.
1.5 -
C.
0.6 -
D.
0.3
Correct Answer: Option A
Explanation
(frac{1}{f} = frac{1}{v} + frac{1}{u})
(frac{1}{v} = frac{1}{f} – frac{1}{u})
(frac{1}{15} – frac{1}{10} = frac{2 – 3}{30})
(frac{1}{v} = frac{-1}{30})
v = – 30 cm
but m = (frac{v}{u} = frac{30}{10} = 3)
Note that the negative sign only shows the placement of the image. It has no effect on the magnification basically.