An object is embedded in a block of ice, 10 cm below the plane surface. if the refractive index of the ice is 1.50, the apparent depth below the surface is
-
A.
2.50 cm -
B.
6.67 cm -
C.
7.50 cm -
D.
7.63 cm
Correct Answer: Option B
Explanation
Refraction index, n = (real depth)/apparent depth
1.5 = (10)/X
X = (10)/1.5 = 6.67 cm