An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5oC per second, calculate the specific heat capacity of the liquid. [Assume no heat is lost]
-
A.
1100Jkg-1K-1 -
B.
320Jkg-1K-1 -
C.
200Jkg-1K-1 -
D.
176Jkg-1K-1
Correct Answer: Option B
Explanation
pt = mc(theta)
C = (frac{pt}{m theta})
= (frac{400 times 1}{0.5 times 2.5})
= 320Jkg-1K-1