An electric generator rated 12 kW, 2 kV distribute power through a cable of resistance 20(Omega). Calculate the power loss in the cable.
-
A.
120 w -
B.
360 w -
C.
720 w -
D.
2400 w
Correct Answer: Option C
Explanation
Power – IV
I = (frac{P}{V})
= (frac{12000}{2000})
I = 6A
Power loss = I(^2)R = 6(^2) x 20
= 720 W