An elastic string of force constant 200N m-1 is stretched through 0.8m within its elastic limit. Calculate the energy stored in the string
-
A.
64.0J -
B.
80.0J -
C.
128.0J -
D.
160.0J
Correct Answer: Option A
Explanation
E = (frac{1}{2}Ke^2)
= (frac{1}{2} times 200(0.8)^2 = 64J)