An atom radiates 1.5 x (10^{-19})J of energy when an electron jumps from one energy level to another. What is the wavelength of the emitted radiation? (Planck’s constant =6.6 x (10^{-34})Js. Speed of light in air=3 x (10^{8}ms^{-1})
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A.
1.32 x (10^{-6})m -
B.
2.98 x (10^{-6})m -
C.
3.32 x (10^{-6})m -
D.
6.82 x (10^{-6})m -
E.
8.01 x (10^{-6})m
Correct Answer: Option A
Explanation
(E=lambda v=frac{hc}{lambda}Rightarrowlambda=frac{hc}{E}={6.6 times10^{-34}times3times10^8}{1.5times10^{-19}}\=1.32times10^{-6})