An ammeter connected to an a.c circuit records 5.5. The peak current in the circuit is
-
A.
7.8A -
B.
7.1A -
C.
3.8A -
D.
3.5A
Correct Answer: Option A
Explanation
(I_o = I_{rms} times sqrt{2} = 5.5 times 1.41 = 7.8A)
(I_o = I_{rms} times sqrt{2} = 5.5 times 1.41 = 7.8A)