An aluminium rod of length 1.8m at 10°C is heated to proceed produce a difference in length of 0.007m. Calculate the temperature to which it is heated. (Linear expansivity of aluminium = 2.3 x 10(^{-5})K(^{-1})
-
A.
155oC -
B.
160oC -
C.
169oC -
D.
179oC
Correct Answer: Option D
Explanation
(alpha = frac{L_2 – L_1}{L_1(theta_2 – theta_1)})
L(_2) – L(_1) = (alpha L_1 (theta_2 – theta_1))
(theta_2 = frac{0.007}{2.3 times 10^{-5} times 1.8}) + 10
= 179°C