A wire, 20m long is heated from a temperature of 5oC to 55oC. If the change in length is 0.020m, calculate the linear expansivity of the wire
-
A.
1.0 x 10-3k-1 -
B.
2.0 x 10-4k-1 -
C.
2.0 x 10-5k-1 -
D.
1.0 x 10-5k-1 -
E.
2.0 x 10-6k-1
Correct Answer: Option C
Explanation
(alpha = frac{Delta L}{L Delta theta} = frac{0.020}{20 times (55 – 5)} = 2.0 times 10^{-5})