A uniform cylindrical block of wood floats in water with one-third of its height above the water level, in a liquid of relative density 0.8, what fraction of its height will be above the liquid level?
-
A.
(frac{1}{6}) -
B.
(frac{1}{5}) -
C.
(frac{1}{3}) -
D.
(frac{4}{5}) -
E.
(frac{5}{6})
Correct Answer: Option E
Explanation
Height inside H2O = (frac{2}{3})
R.d = (frac{text{height inside}H_2O}{text{height inside liquid}})
0.8 = (frac{frac{2}{3}}{X})