A thermometer with an arbitrary scale S, of equal division registers -30oS at the ice point and +90oS at the steam point. Calculate the Celsius temperature corresponding to 60oS
-
A.
25.0oC -
B.
50.0oC -
C.
66.7oC -
D.
75.0oC
Correct Answer: Option D
Explanation
100oC … 90oS
(theta)oC … 60oS
0oC … 30oS
(frac{theta – 0}{100 – 0}) = (frac{60 – (-30)}{90 – (-30)})
(theta) = 75oC