A stone projected horizontally from the top of a tower with a speed of 4 ms(^{-1}) lands on the level ground at a horizontal distance of 25 m from the foot of the tower. Calculate the height of the tower. = 10 ms(^{-2})]
Explanation
R = U(sqrt{frac{2h}{g}})
h = (frac{R^2g}{2u^2})
= (frac{25^2 times 10}{2 times 4^2})
= 195.3m