A stone is projected vertically upward with a speed of 30ms(^{1}) from the top of a tower of height 50 m. Neglecting air resistance, determine the maximum height it reached from the ground. [g = 10 ms(^-2)]
Explanation
V(^2 = U^2 – 2gs)
S = (frac{V^2 – U^2}{-2g} = frac{O^2 – 30^2}{-2 times 20}) = 45m
Height from ground = 50 + 45 = 95m
Height from ground = 50 + 45 = 95m