A spring of force constant 500 NM-1 is compressed such that its length shortens by 5cm. The energy stored in the spring is?
-
A.
0.625 J -
B.
6.250 J -
C.
62.500 J -
D.
625.000 J
Correct Answer: Option A
Explanation
Energy stored in a spring = (1)/2 K e2 = (1)/2 x 500(0.05)2 = 0.625J