A source of sounds produces waves in air of wavelength1.65m. If the speed of sound in air is 330ms-1 the period of vibration in seconds is
-
A.
200 -
B.
2.0 -
C.
0.5 -
D.
0.02 -
E.
0.005
Correct Answer: Option E
Explanation
T = λ/v
T = 1.65/330 = 0.005