A sonometer wire of length 100cm under a tension of 10N, has a frequency of 250Hz. Keeping the length of the wire constant, the tension is adjusted to produce a new frequency of 350Hz. The new tension is
-
A.
5.1N -
B.
7.1N -
C.
14.0N -
D.
19.6N
Correct Answer: Option D
Explanation
(frac{F_1}{F_2}) = (sqrtfrac{T_1}{T_2})
(frac{250}{350}) = (sqrtfrac{10}{T_2})
T2 = 19.6N