A solid weight 45N and 15N respectively in air and water. Determine the relative density of the solid
-
A.
0.33 -
B.
0.50 -
C.
1.50 -
D.
3.00
Correct Answer: Option C
Explanation
R.d = (frac{text{weight in air}}{text{apparent loss of weight in water}} = frac{45}{45 – 15})
= (frac{45}{30} = 1.50)