A solid weighs 4.8g in air, 2.8g in water and 3.2g in kerosine. The ratio of density of the solid to that of the kerosine is
-
A.
12 -
B.
3 -
C.
2 -
D.
(frac{3}{2}) -
E.
(frac{5}{4})
Correct Answer: Option B
Explanation
Relative density of solid = (frac{text{weight of solid}}{text{weight of an equal volume of water}})
(frac{4.8}{4.8 -3.2}) = (frac{4.8}{2}) = 2.4
Ratio of density of liquid = (frac{text{weight of liquid kerosine}}{text{weight of an equal volume of water}})
= (frac{4.8 – 3.2}{4.8 – 2.8}) = (frac{1.6}{2})
= 0.8
= (frac{text{density of solid}}{text{density of kerosine}})
= (frac{2.4}{0.8}) = 3