A solid cube of side 50cm and mass 75kg floats in a liquid with (frac{1}{3}) of its height above the liquid surface. The relative density of the liquid is?
-
A.
0.33 -
B.
0.50 -
C.
0.67 -
D.
0.90
Correct Answer: Option D
Explanation
Volume of liquid displaced
= (frac{2}{3})(0.5)(^3)
Mass of liquid displaced = mass of floating cube = 75kg
Density of liquid = (frac{mass}{volume})
= (frac{75}{(frac{7}{3(0.5)})}) × 3
= 0.9 × 103kgm(^{-3})
R.D of liquid = (frac{(0.9 )}{(1.0)}) × 103
= 0.9
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