Simplify : (frac{1frac{1}{4} + frac{7}{9}}{1frac{4}{9} – 2frac{2}{3} times frac{9}{64}}) (b) Given that (sin x…

(a) Simplify : (frac{1frac{1}{4} + frac{7}{9}}{1frac{4}{9} – 2frac{2}{3} times frac{9}{64}})

(b) Given that (sin x = frac{2}{3}), evaluate, leaving your answer in surd form and without using tables or calculator, (tan x – cos x).

Explanation

(a) (frac{1frac{1}{4} + frac{7}{9}}{1frac{4}{9} – 2frac{2}{3} times frac{9}{64}})

(1frac{1}{4} + frac{7}{9} = frac{5}{4} + frac{7}{9})

= (frac{45 + 28}{36})

= (frac{73}{36})

(1frac{4}{9} – 2frac{2}{3} times frac{9}{64} = frac{13}{9} – (frac{8}{3} times frac{9}{64}))

= (frac{13}{9} – frac{3}{8})

= (frac{104 – 27}{72})

= (frac{77}{72})

(therefore frac{1frac{1}{4} + frac{7}{9}}{1frac{4}{9} – 2frac{2}{3} times frac{9}{64}} = frac{73}{36} div frac{77}{72})

= (frac{73}{36} times frac{72}{77})

= (frac{146}{77})

= (1frac{69}{77})

(b) (sin x = frac{2}{3}) 

  In (Delta ABC, 3^{2} = 2^{2} + |BC|^{2})

(therefore |BC|^{2} = 9 – 4 = 5)

(|BC| = sqrt{5})

(tan x = frac{2}{sqrt{5}} ; cos x = frac{sqrt{5}}{3})

(therefore tan x – cos x = frac{2}{sqrt{5}} – frac{sqrt{5}}{3})

= (frac{6 – 5}{3sqrt{5}})

= (frac{1}{3sqrt{5}})

Rationalizing, we have

(frac{1}{3sqrt{5}} times frac{sqrt{5}}{sqrt{5}} = frac{sqrt{5}}{15})

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