A simple pendulum with a period of 2.0s has its length doubled. Its new period is
-
A.
1.00s -
B.
1.41s -
C.
0.3s -
D.
2.83s -
E.
4.00s
Correct Answer: Option D
Explanation
Using (frac{T_1}{T_2}) = (sqrtfrac{L_1}{L_2})
(frac{2}{T_2}) = (sqrtfrac{L_1}{2L_1})
T2 = 2.83sec