A ship H leaves a port P and sails 30 km due south. Then it sails 50km due west. What is the bearing of H from P?
-
A.
20o 34′ -
B.
243o 26′ -
C.
116o 34′ -
D.
63o 26′ -
E.
240o 56′
Correct Answer: Option B
Explanation
Let the bearing of H from P be represented by x°.
(tan theta = frac{30}{60} = 0.5)
(theta = tan^{-1} (0.5) = 26.565°)
(x = 180° + (90 – 26.565))
(x = 180 + 63.435 = 243.435°)
= (243° 26′)