A rod of initial lenght 2m at a temperature of 25oC is heated to 80oC. Calculate the increase in length of the rod if its linear expansivity is 4.0 x 10-3K-1
-
A.
0.26m -
B.
0.44m -
C.
0.53m -
D.
0.84m
Correct Answer: Option B
Explanation
(l_2 – l_1 = alpha l_1 (theta_2 – theta_1) = 4.0 times 10^{-3} times 2(80 – 25))
= 0.44m