A rocket is launched from the surface of the earth. If the radius of the earth is 6.4 x 106m and the acceleration of free fall due to gravity is 1Oms-1 calculate the escape velocity of the rocket.
-
A.
2.53 x 104ms-1 -
B.
1.13 x 104ms -
C.
8.00 x 103ms-1 -
D.
4.23 x 103ms-1 -
E.
6.41 x 104ms-1
Correct Answer: Option B
Explanation
V = √2gR
V = √2 x 10 x 6.4 x 102
1.13 x 104ms