A resistance thermometer has a resistance of 20(Omega) at 0oC and 85(Omega) at 100oC. If its resistance is 52(Omega)in a medium, calculate the corresponding temperature
-
A.
49.2oC -
B.
60.6oC -
C.
80.0oC -
D.
84.7oC
Correct Answer: Option A
Explanation
85(Omega) ……..100oC
52(Omega) ……..(theta)oC
20(Omega) ……..0oC
(frac{52 – 20}{85 – 20} = frac{theta – 0}{100 – 0})
(theta = frac{32 times 100}{65} = 49.2^oC)