A ray of light is incident at an angle of 30o on a glass prism of refractive index 1.5. Calculate the angle through which the ray is minimally deviated in the prism. (The medium surrounding the prism is air)
-
A.
10.5o -
B.
19.5o -
C.
21.1o -
D.
38.9o -
E.
40.5o
Correct Answer: Option A
Explanation
n = (frac{sin i}{sin r})
sin r = (frac{30^o}{n})
sin r = (frac{0.5}{1.5})
sin r = 0.3333
r = 19.5o; Deviation 30 – 19.5 = 10.5o