A primary alkanol has a molecular mass of 60. What is the structural formula of the compound? [C= 12.0, H= 1.0, O= 16.0)
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A.
A -
B.
B -
C.
C -
D.
D
Correct Answer: Option B
Explanation
Alkanols have the formula (C_{n}H_{2n+1}OH).
⇒ ( 12n + (1times (2n+1)) + 16.0 + 1.0 = 60)
= (14n +18 = 60)
(n = frac{60-18}{14} = frac{42}{14} = 3)
Hence, the alkanol is gotten by putting n=3,
=(C_{3}H_{7}OH)