A piece of metal of relative density 5.0 weighs 60N in air. Calculate its weight when fully immersed in water
-
A.
4N -
B.
5N -
C.
48N -
D.
60N
Correct Answer: Option C
Explanation
R.D = (frac{m}{m – m_2} = 5 = frac{6}{60 – m_1} = frac{240}{5} = 48N)
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