A particle of charge 5C moves perpendicularly to a magnetic Held of magnitude C.01 T….

A particle of charge 5C moves perpendicularly to a magnetic Held of magnitude C.01 T. If the velocity of the charge is 1.5ms’2, calculate the magnitude of the force exerted on the particle
  • A.
    0.050 N
  • B.
    0.075N
  • C.
    0.0300N
  • D.
    3.300N
  • E.
    0.000N
Correct Answer: Option B
Explanation

F = eV = 0.01 x 5 x 1.5 = 0.075N

You May Also Like