A particle is projected horizontally at 10 ms(^{-1}) from a height of 45m. Calculate the…

A particle is projected horizontally at 10 ms(^{-1}) from a height of 45m. Calculate the horizontal distance covered by the particle before hitting the ground. [g = 10ms(^{-1})]

Explanation

(h = frac{1}{2} gt^2) t = (sqrt{frac{2h}{g}})

= (sqrt{frac{2 times 45}{10}}) = 3s

Horinzntal distance = vt = 10 x 3 = 30m

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