A particle is projected at an angle of 30° to the horizontal with a speed of 250 ms(^{-1}). Calculate the;
(a) total time of flight of the particle;
(b) speed of the particle at its maximum height. [ g = 10 ms(^{-2})]
Explanation
(a) T = (frac{2Usintheta}{g} = frac{2 times 250 times sin 30}{10})
= 25s
(b) Speed at h(_{text{max}} Ucos theta)
= 250 cos 30(^o) = 216m/s