A parallel plate capacitor of capacitance 600(mu F) has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor
-
A.
1.2C -
B.
3.3C -
C.
3330.0C -
D.
12.0000.0C
Correct Answer: Option A
Explanation
Q = CV
= 600 x 10-6 x 200 = 1.2C