A near sighted student has a near point of 0.1m and a focal length of…

A near sighted student has a near point of 0.1m and a focal length of 5.0cm. What is the student’s far point?
  • A.
    0.200m
  • B.
    8.000m
  • C.
    0.125m
  • D.
    2.100m
  • E.
    No Correct Option
Correct Answer: Option E
Explanation

The person’s image distance v will be at the distance of 0.1m = 10cm for him to see objects at a distance of u.F = 5.0cm
( frac{1}{v} + frac{1}{u} = frac{1}{f} implies frac{1}{10} + frac{1}{u} = frac{1}{5} \
frac{1}{u} = frac{1}{5} – frac{1}{10} = frac{2-1}{10} = frac{1}{10} \
text{therefore } u = 10cm = 0.1m )

You May Also Like

List the integral values of x which satisfy the inequality -1 List the integral values of x which satisfy the inequality -1 A. -1, 0, 1, 2 B. 0, 1, 2, 3 C. -0, 1, 2, 3 D. -1, 0, 2, 3 Correct Answer: Option A Explanation -1 = 2x Integral value of x are -1, 0, 1, 2 `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })

List the integral values of x which satisfy the inequality -1 A. -1, 0, 1, 2 B. 0,…
Read More