A mixture of 0.20 mole of Ar, 0.20 mole of N2 and 0.30 mole of He exerts a total pressure of 2.1 atm. The partial pressure of He in the mixture is?
-
A.
0.90 atm -
B.
0.80 atm -
C.
0.70 atm -
D.
0.60 atm
Correct Answer: Option A
Explanation
Total no mole = 0.2 + 0.2 + 0.3 = 0.7
Partial pressure of He = (0.3)/(0.7) x 2.1 =0.90