A milliameter with full scale deflection of 10mA has an internal resistance of 5 ohms….

A milliameter with full scale deflection of 10mA has an internal resistance of 5 ohms. It would be converted to an ammeter with a full scale deflection of 1A by connecting a resistance of
  • A.
    (frac{5}{99})ohms in series with it
  • B.
    (frac{5}{99})ohms in parallel with it
  • C.
    (frac{99}{5})ohms in series with it
  • D.
    (frac{99}{5})ohms in parallel with it
  • E.
    2 ohms in series with it
Correct Answer: Option B
Explanation

I = 1 – (10 x 10-3)
= 0.99A
IR = 10 x 10 x 10-3 x 5
R = (frac{5}{99})(Omega)

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