A milliameter of resistance 5(Omega) and full scale deflection of 5m A is to used to measure a potential difference of 50 V. The resistance of the multiplier should be
-
A.
95(Omega) -
B.
110(Omega) -
C.
595(Omega) -
D.
995(Omega) -
E.
1005(Omega)
Correct Answer: Option D
Explanation
V = IR
50 = 50 x 10-3 (5 + R)
R = 995(Omega)