A metallic bar 50 cm long has a uniform cross-sectional area of 4.0 cm(^2). If a tensile force of 35 kN produces an extension of 0.25 mm, calculate the value of Young’s modulus
Explanation
E (frac{Fl}{Ae})
= (frac{35 times 10^3 times 50 times 10^{-2}}{4 times 10^{-4} times 0.25 times 10 ^{-3}})
= 1.75 x 10(^{11})Nm(^{-2})